Asked by Sarah
the amount (in milligrams) of a drug in the body t hours after taking a pill is given by A(t)=30(0.8)t .
(a) What is the initial dose given?
(b) What percent of the drug leaves the body each hour?
Percent:
(c) What is the amount of drug left after 9 hours?
(d) What is the first whole number of hours at which there is less than 5 milligrams left in the body?
(a) What is the initial dose given?
(b) What percent of the drug leaves the body each hour?
Percent:
(c) What is the amount of drug left after 9 hours?
(d) What is the first whole number of hours at which there is less than 5 milligrams left in the body?
Answers
Answered by
Steve
(a) at t=0, .8^0 = 1
(b) .8 means decrease of 20%
(c) 30*.8^9 = ?
(d) 30*.8^t = 5
.8^t = 1/6
t log(.8) = log(1/6)
t = log(1/6)/log(.8) = 8.03
(b) .8 means decrease of 20%
(c) 30*.8^9 = ?
(d) 30*.8^t = 5
.8^t = 1/6
t log(.8) = log(1/6)
t = log(1/6)/log(.8) = 8.03
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.