Asked by Bryce
This is a stoichiometry equation.
Cu(s) + 4(HNO3)(aq) -> Cu(NO3)2(aq) + 2(NO2)(g)+2(H2O)(l)
If you use 6 moles of nitric acid 4(HNO3), how many moles of Copper (II) Nitrate Cu(No3)2 will be produced?
Cu(s) + 4(HNO3)(aq) -> Cu(NO3)2(aq) + 2(NO2)(g)+2(H2O)(l)
If you use 6 moles of nitric acid 4(HNO3), how many moles of Copper (II) Nitrate Cu(No3)2 will be produced?
Answers
Answered by
Damon
HNO3/CU(NO3)2 = 4 mols /1 mol
so
6/x = 4/1
4 x = 6
x = 1.5
so
6/x = 4/1
4 x = 6
x = 1.5
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.