Question

A solution containing equal masses of glycerol, C3H8O3, and water has a density of 1.10 g/mL. Calculate the molality of glycerol.

I got 11.9 m.

Answer 1

Assume 1000ml of the solution.
total mass=1000ml/density=1100g

moles of glycerol=550/molmassgly /1L=550/92.1= not your answer.

Answer 2

Step 1:

Make the assumption that glycerol and water has 50g since they have equal masses

Step 2:

Convert grams of glycerol to moles. If you don't know how to do that then I'd quit chem right now...

moles of C3H8O3=.543

Step 3:

convert the 50g of water into kg.

kg water= .05

Step 4:

Set up molality equation:
(.543)/(.05)= 10.9m

Answer: 10.9m