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Asked by Deepa

A rock is tossed straight up with a velocity of 37.1 m/s. When it returns, it falls into a hole 18.8 m deep.

How long is the rock in the air, from the instant it is released until it hits the bottom of the hole?
17 years ago

Answers

Answered by bobpursley
hfinal=hinitial+vi*time -1/2 9.8 time^2

hfinal is -18.8 hinital is zero.

solve for time, notice it is a quadratic.
17 years ago

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