Asked by Kevin
                A rock is tossed straight up into the air. The height h (in feet) t seconds after it is tossed is given by
the function:
h(t)=-16t^2+100.4t+5.1
(a) Make a table of values for 0 to 10 seconds.
(b) Graph the function.
(c) What is the initial height of the rock?
(d) When did the rock reach its maximum height? What is that height?
(e) At what time did the rock hit the ground?
            
        the function:
h(t)=-16t^2+100.4t+5.1
(a) Make a table of values for 0 to 10 seconds.
(b) Graph the function.
(c) What is the initial height of the rock?
(d) When did the rock reach its maximum height? What is that height?
(e) At what time did the rock hit the ground?
Answers
                    Answered by
            Damon
            
    No one, like no one, uses feet any more for physics problems but anyway
It is a parabola (uppside down, sheds water)
c) at t = 0, h = 5,1
d) find the vertex by completing the square or know that the rock is at the top when the velocity is zero which is when
-32 t + 100.4 = 0
t = 3.14 seconds to top
h = -16(3.14)^2 +100.4(3.14) + 5.1
= -158 + 315 +5.1 = 162 feet
e) solve quadratic for roots and use positive t
3.14+/-3.19
use t = 6.33 seconds
    
It is a parabola (uppside down, sheds water)
c) at t = 0, h = 5,1
d) find the vertex by completing the square or know that the rock is at the top when the velocity is zero which is when
-32 t + 100.4 = 0
t = 3.14 seconds to top
h = -16(3.14)^2 +100.4(3.14) + 5.1
= -158 + 315 +5.1 = 162 feet
e) solve quadratic for roots and use positive t
3.14+/-3.19
use t = 6.33 seconds
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