Asked by Bryan
Do the following calculations for a 1150 kg car. a. How much work must be done on the car to accelerate it from 0 to 60 km/h.
**** Hi I am looking for advice on my questions below. This is my attempt at answering them.. Am i at least on the right track?
Ek=1/2mv^2
=1/2(1150)(16.67)
=9.6x10^3J
b. If the car can do this is 13 s, what is the power of the motor?
P=W/t
=9.6x10^3/13s = 738Watts
c. If a breaking force of 500 N is applied, how long (time) does it take to stop the car.
Ft=mV
t=mV/F
t= (1150)(16.67)/ 500N = 38.34s
d. What distance does the car travel while braking?
fd=1/2mv^2
500*d= 1/2 (1150) (16.67)^2
500 *d= (575)(277.9)
d=1.6x10^5 / 500
d=320m
**** Hi I am looking for advice on my questions below. This is my attempt at answering them.. Am i at least on the right track?
Ek=1/2mv^2
=1/2(1150)(16.67)
=9.6x10^3J
b. If the car can do this is 13 s, what is the power of the motor?
P=W/t
=9.6x10^3/13s = 738Watts
c. If a breaking force of 500 N is applied, how long (time) does it take to stop the car.
Ft=mV
t=mV/F
t= (1150)(16.67)/ 500N = 38.34s
d. What distance does the car travel while braking?
fd=1/2mv^2
500*d= 1/2 (1150) (16.67)^2
500 *d= (575)(277.9)
d=1.6x10^5 / 500
d=320m
Answers
Answered by
Chanz
looks good
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