Asked by DS
In a figure, ABCD is a rectangle in which AD=43.7 cm, DE=100 cm and EDC =27°, where E is a point above C making a rught angled triangle DEC above the rectangle.
Find angle EAD.
I found the other parts of this question but thjs one's difficult. I assumed AB as the rectangle's base and DC as the triangle's basee i.e the top of the rectangle.
Thanks
Find angle EAD.
I found the other parts of this question but thjs one's difficult. I assumed AB as the rectangle's base and DC as the triangle's basee i.e the top of the rectangle.
Thanks
Answers
Answered by
Steve
ADE=90+27=117°
using the law of cosines,
AE^2 = 43.7^2 + 100^2 - 2*43.7*100*cos117°
So, AE=126
Now use the law of sines:
sin(EAD)/100 = sin(117°)/126
using the law of cosines,
AE^2 = 43.7^2 + 100^2 - 2*43.7*100*cos117°
So, AE=126
Now use the law of sines:
sin(EAD)/100 = sin(117°)/126