Question

in the given figure ABCD is a trapezium in which AD parallel to BC. Angle ABC= 90degree. AD=16cm, AC=41cm and BC=40cm.find the area of the trapezium.

Answer 1

since angle B is a right angle, AB is the height of the trapezoid. So, the area is

(16+40)/2 * √(41^2 - 40^2)

Answer 2

Gajaj

Answer 3

252cm