Asked by lindokuhle mahlamvu
An object with a mass of 2kg is moving at 8m.s-1 a net force acts on iy for 7s,after which it moves at 10m.s-1 in the opposite direction. The magnitude and direction of the net force is
Answers
Answered by
Chanz
Ft = change(mv)
so F = change(mv)t = mvf-mvi/t =
8-(-10)/7 = 18/7
so F = change(mv)t = mvf-mvi/t =
8-(-10)/7 = 18/7
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