Asked by Ethan
An architect wants to design a window in the shape of a rectangle capped by a semicircle. If the perimeter of the window is constrained to be 24 feet, what dimensions should the architect choose for the window in order to admit the greatest amount of light?
Answers
Answered by
Steve
If the width is x and the rectangle's height is y, then
x+2y + π/2 x = 24
so, y = (24-(1+π/2)x)/2
The area is
a = xy + π/2 (x/2)^2
= x(24-(1+π/2)x)/2 + π/8 x^2
= 12x - (1/2 + π/8)x^2
Now just set da/dx=0 to find where the max occurs. Or, use what you know about the vertex of a parabola.
x+2y + π/2 x = 24
so, y = (24-(1+π/2)x)/2
The area is
a = xy + π/2 (x/2)^2
= x(24-(1+π/2)x)/2 + π/8 x^2
= 12x - (1/2 + π/8)x^2
Now just set da/dx=0 to find where the max occurs. Or, use what you know about the vertex of a parabola.
Answered by
Nasri
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