Asked by Anonymous
During the initial stage of launching a spacecraft vertically, the acceleration a(in m/s^2) is a=6t^2. Find the velocity in the spacecraft after 6 seconds.
Answers
Answered by
Steve
a = dv/dt, so
v(t) = 2t^3 = 2*6^3
v(t) = 2t^3 = 2*6^3
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