Asked by Kay
What is the area of a pentagon with sides of equal length, measuring 5v+3?
Answers
Answered by
Reiny
Assuming we have a regular pentagon,
form central triangles, there will be 5 equal ones
Each one is an isosceles triangle with a central angle of 72°
and two equal angles of 54°
we need the height, h
tan 54 = h/((1/2)(5v+3))
h = (1/2)(5v+3) tan 54
area of one of them
= (1/2) base x height
= ...
total area is 5 times that
you do the algebra
form central triangles, there will be 5 equal ones
Each one is an isosceles triangle with a central angle of 72°
and two equal angles of 54°
we need the height, h
tan 54 = h/((1/2)(5v+3))
h = (1/2)(5v+3) tan 54
area of one of them
= (1/2) base x height
= ...
total area is 5 times that
you do the algebra
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.