Question

a number of two digits divided by the sum of the digits the quotient is 7 and the remainder is 6 . if the digits of the number are interchanged, the resulting number exceeds three times the sum of the digits by 5.

Answer 1

let the unit digit be x
let the tens digit by y
the number is 10y + x
the number reversed is 10x + y

translate the English to Math
(Math is a language)

"divided by the sum of the digits the quotient is 7 and the remainder is 6 "

(10y+x)/(x+y) = 7 + 6/(x+y)
times (x+y)
10y + x = 7(x+y) + 6
10y + x = 7x + 7y + 6
3y - 6x = 6
y - 2x = 2
y = 2x+2

" if the digits of the number are interchanged, the resulting number exceeds three times the sum of the digits by 5"
10x + y = 3(x+y) + 5
10x + y = 3x + 3y + 5

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