Seven years ago a women was four times old as her sons age at that time.In seven years years from now the mother will be twice as old as her son would be then.Find their present ages.

Question

Answer

Answer 1

If the woman is w, and the son is s, then we know

w-7 = 4(s-7)
w+7 = 2(s+7)

woman is 35, son is 14

Answer 2

I don't know ple solve it

Answer 3

I CAN'T SOLVE IT