Asked by latief

Seven years ago a women was four times old as her sons age at that time.In seven years years from now the mother will be twice as old as her son would be then.Find their present ages.


Answer
Answered by Steve
If the woman is w, and the son is s, then we know

w-7 = 4(s-7)
w+7 = 2(s+7)

woman is 35, son is 14
Answered by Anonymous
I don't know ple solve it
Answered by value
I CAN'T SOLVE IT
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