Asked by luckson mulanshi
a bullet of mass 20g travelling at 16m/s penetrates a brock of wood and it comes to rest in 0.5seconds.find(a)the acceralation (b)the average redating force(c)the depth of the penetration
Answers
Answered by
MathMate
Assuming that the wood block is fixed and stationary.
(a)
acceleration, a
= (final vel. - initial vel) / time
= (v-u)/t
= (0-16 m/s) / 0.5
= -32 m/s²
(b)
average force
= mass * acceleration
= 0.020 kg * 32 m/s²
= 0.64 newton
(c)
Distance, S
= ut+(1/2)at²
= 16*0.5+(1/2)*(-32)*(0.5^2)
= 8+(-4)
= 4 m
(a)
acceleration, a
= (final vel. - initial vel) / time
= (v-u)/t
= (0-16 m/s) / 0.5
= -32 m/s²
(b)
average force
= mass * acceleration
= 0.020 kg * 32 m/s²
= 0.64 newton
(c)
Distance, S
= ut+(1/2)at²
= 16*0.5+(1/2)*(-32)*(0.5^2)
= 8+(-4)
= 4 m
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