Asked by Arianna
Which equation has intercepts x(1, 0, 0), y(0, -1, 0), and z(0, 0, 2)?
3x-2y+6z=12
2x-2y+z=2
4x-4y+z=4
x-y+2z=4
My answer- 2x-2y+2=2
3x-2y+6z=12
2x-2y+z=2
4x-4y+z=4
x-y+2z=4
My answer- 2x-2y+2=2
Answers
Answered by
Steve
That does not work: 2(1)-2(-1)+2 = 6
Better try again.
Better try again.
Answered by
Arianna
4x-4y+z+4?
Answered by
Steve
I don't see any choices which work. I suspect a typo.
Answered by
Arianna
There was no typo, I had just submitted my quiz and the choice I originally picked was correct.
Answered by
Steve
4(1)-4(-1)+2 = 4+4+2 = 10
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