Question

a uniform beam 6.0 metre long and weighing 4kg rests on support at p and q placed left and right 1.0 metres from each end of the beam weights of mass 10 kg and 8kg are placed near p and q respectively one each end of the beam.calculate the reaction at p and q?

Answer 1

p and q are 4.0 m apart

moments around q
4 p = (10 * 5) + (4 * 2) - (8 * 1)
p = 12.5
Rp = 12.5 g

moments around p
4 q = (8 * 5) * (4 * 2) - (10 * 1)
q = 9.5
Rq = 9.5 g

Answer 2

clarifying

Rp = 12.5 * g

Rq = 9.5 * g

Answer 3

I don't know that why am asking you

Answer 4

i need more clarity on why it had to be done that way

Answer 5

I dont understand the calculation

Answer 6

i doot understand the calculation

Answer 7

Correct

Answer 8

am not getting the sense

Answer 9

i dont understand the solutions

Answer 10

I want to learn physics very well

Answer 11

Pls if possible can you snap and post
the diagram for clarity

Answer 12

Correct

Answer 13

Tnks

Answer 14

After sketching the diagram.
P+Q=220 N (Newton)
Taking moment about point P
40*2 + 80*5 = 4Q +100*1
80 + 400 = 4Q + 100
480 - 100 = 4Q
380 = 4Q
Q = 380/4
Q = 95 N
P + Q = 220 N
P +95 = 220
P = 220 - 95 = 125 N
P =125 N

Answer 15

I kind of understood 90 percent of what this person nkanu did but I don't understand that 4Q, how Q is 4Q

Answer 16

How did you get 220N

Answer 17

Pls be more specific and do show more workings on this particular question because am also confused

Answer 18

Thank you very much Nkanu.But could you post the diagram

Answer 19

Awesome .thanks I understood it all

Answer 20

I understood the solving but pls can u sketch the diagram for better understanding

Answer 21

Thanks so much but pls clarify more onthe diagram

Answer 22

What is *

Answer 23

Pls sketch the diagram

Answer 24

Please I don't understand, can you throw more lights?.

Answer 25

I don't understand the explanation here😔😔

Answer 26

How did u get 220