Asked by Larisa
What is the likely identity of a substance (see Table 10-1) if a sample has a mass of 9.38 g when measured in air and an apparent mass of 8.55 g when submerged in water?
A)Copper
B)Iron or steel
C)Aluminum
D) Lead
E)Concrete
F)Gold
A)Copper
B)Iron or steel
C)Aluminum
D) Lead
E)Concrete
F)Gold
Answers
Answered by
bobpursley
assume a volume d.So the mass of the volume displaced is v*1g/cm^3
mass object=9.38
masssubmerged+masswaterdisp=9.38
8.55+v*1g/cm^3=9.38
solve for volume v
density=mass/volume=9.38/volume
then, compare that number with the mass of the elements/substances above.
mass object=9.38
masssubmerged+masswaterdisp=9.38
8.55+v*1g/cm^3=9.38
solve for volume v
density=mass/volume=9.38/volume
then, compare that number with the mass of the elements/substances above.
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