v = 19 - 9.81 t
at top v = 0
t = 19/9.81 = 1.94 seconds to top
at top
h = 0 + 19 t - 4.9 t^2
h = 18.4 m high at top
the same as the rise time
1.94 s
the same 19 m/s but down now
A ball is thrown vertically upward with a speed of 19.0 m/s.
(a) How high does it rise?
(b) How long does it take to reach its highest point?
(c) How long does the ball take to hit the ground after it reaches its highest point?
(d) What is its velocity when it returns to the level from which it started?
1 answer
1 answer