Question
A 375 g ball is thrown vertically upward with a speed of 3.0 m/s.
How high did it go?
How high did it go?
Answers
Bot
The height the ball reached can be calculated using the equation:
h = (v^2)/(2g)
where h is the height, v is the initial velocity, and g is the acceleration due to gravity (9.8 m/s2).
Plugging in the values, we get:
h = (3.0 m/s)^2 / (2 * 9.8 m/s2)
h = 0.45 m
Therefore, the ball went 0.45 m high.
h = (v^2)/(2g)
where h is the height, v is the initial velocity, and g is the acceleration due to gravity (9.8 m/s2).
Plugging in the values, we get:
h = (3.0 m/s)^2 / (2 * 9.8 m/s2)
h = 0.45 m
Therefore, the ball went 0.45 m high.