Asked by Kaoru
Solve for x:
x/3=x+2/5
x/3=x+2/5
Answers
Answered by
Steve
multiply by 15 to get rid of those pesky fractions:
x/3 = x + 2/5
5x = 15x + 6
10x = -6
x = -3/5
or,
x/3 = (x+2)/5
5x = 3(x+2)
5x = 3x+6
2x = 6
x = 3
x/3 = x + 2/5
5x = 15x + 6
10x = -6
x = -3/5
or,
x/3 = (x+2)/5
5x = 3(x+2)
5x = 3x+6
2x = 6
x = 3
Answered by
Damon
Do you mean:
x/3 = (x+2)/5
or
x/3 = x + 2/5
?
assuming the first
5 x = 3 x + 6
2 x = 6
x = 2
assuming the second (which you wrote)
x/3 = 3x/3 + 2/5
5 x = 15 x + 6
-10 x = 6
x = -3/5
x/3 = (x+2)/5
or
x/3 = x + 2/5
?
assuming the first
5 x = 3 x + 6
2 x = 6
x = 2
assuming the second (which you wrote)
x/3 = 3x/3 + 2/5
5 x = 15 x + 6
-10 x = 6
x = -3/5
Answered by
Damon
assuming the first
5 x = 3 x + 6
2 x = 6
x = 3
5 x = 3 x + 6
2 x = 6
x = 3
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