Question
A tennis player strikes a ball when it is 2.20m above the ground, with a velocity 18.7 m/s at 20 degrees above the horizontal. The net is 5m away horizontally and it is 0.90m high. after 0.37 seconds, what is the direction of the ball with respect to the horizontal?
Answers
Henry
Vo = 18.7m/s[20o].
Xo = 18.7*Cos20 = 17.6 m/s.
Yo = 18.7*sin20 = 6.40 m/s
Y = Yo + g*t = 6.40 - 9.8*0.37 = 2.77 m/s.
Tan A = Y/Xo = 2.77/17.6 = 8.94o = Direction.
Xo = 18.7*Cos20 = 17.6 m/s.
Yo = 18.7*sin20 = 6.40 m/s
Y = Yo + g*t = 6.40 - 9.8*0.37 = 2.77 m/s.
Tan A = Y/Xo = 2.77/17.6 = 8.94o = Direction.
Henry
Tan A = Y/X = 2.77/17.6 = 0.15737
A = 8.94o = Direction.
A = 8.94o = Direction.