A tennis player hits a ball 2.0 m above the ground. The ball leaves his racquet with a speed of 15.0m/s at an angle 5.3∘ above the horizontal. The horizontal distance to the net is 7.0 m, and the net is 1.0 m high. How much did it clear the net by?

Answer 1

find horizontal velocity.
find time to reach net
time=distance/horizontal velocity

Now find height at that net point time, due to the vertical velocity and time.
hf=hi+viv^t-1/2 g t^2

is that higher than the net?

Answer 2

no

Answer 3

yes