Asked by John
A tennis player hits a ball 2.0 m above the ground. The ball leaves his racquet with a speed of 15.0m/s at an angle 5.3∘ above the horizontal. The horizontal distance to the net is 7.0 m, and the net is 1.0 m high. How much did it clear the net by?
Answers
Answered by
bobpursley
find horizontal velocity.
find time to reach net
time=distance/horizontal velocity
Now find height at that net point time, due to the vertical velocity and time.
hf=hi+viv^t-1/2 g t^2
is that higher than the net?
find time to reach net
time=distance/horizontal velocity
Now find height at that net point time, due to the vertical velocity and time.
hf=hi+viv^t-1/2 g t^2
is that higher than the net?
Answered by
nnn
no
Answered by
nnn
yes
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