Asked by mike

a car weighing 1600kg moving with a velocity of 30 meter per second retarded uniformly coming to rest in 20 seconds calculate
1, initial momentum
2, final momentum
3, rate of change of momentum
4,acceleration of the car
5, magnitude of the force apply

Answered by Steve
(1) 1600*30
(2) 0
(3) p = mv, so dp/dt = m dv/dt = 1600*(0-30)/(20-0) = -2400 kg-m/s
(4) see (3)
(5) F = ma
Answered by Prachi jain
Samaj nahi aaya explain briefly
Answered by Jyoti
1) initial momentum =mv
Mass =1600 kg
Velocity =30m/sec
=1600 *30=4800 kg m/s
2)final momentum=mv
If it is slowing down then the final velocity = 0m/Sec
Mass =1600kg
=mv
1600*0=0 kg m/sec
3)rate of change of momentum =m1u1 +m2u2=m1v1+m2v2
U = initial velocity =0m/sec
V=final velocity =30m/sec
Mass = 1600kg
1600*0+1600*0=1600*30+1600*30
0=4800+4800
Rate of change of momentum =9600
Answered by Thor
Ur ans 3 is wrong
Rate of change of momentum is 2400 N
Plz always check and then post, how can anyone be this much irresponsible
Answered by Anonymous
What is answer 4 and 5
Answered by Anonymous
BakwashšŸ¤£
Answered by Anonymous
Thoda aur sahi se samjao
Answered by Krishna bhakat
Isme kuch clear nahi ho raha hai
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