a) KE = 1/2 * m * v^2 (Joules)
... minus zero from start
b) see a) ... work & energy the same
c) d = 1/2 * a * t^2 (meters)
d) f = m * a (Newtons)
A 1600kg car starts at rest and reaches 40 m/s in 6 seconds.
I need to find:
a) the change in kinetic energy
b) work
c) distance
d) applied force of the engine
1 answer
1 answer