Asked by Help Please
Boat A leaves a dock headed due east at 1:00 PM traveling at a speed of 16 mi/hr. At 2:00 PM, Boat B leaves the same dock traveling due north at a speed of 18 mi/hr. Find an equation that represents the distance d in miles between the boats and any time t in hours for t≥1 , using that t=0 corresponds to the time that Boat A leaves the dock.
Answers
Answered by
Steve
We have a right triangle whose hypotenuse is the distance (d) between the boats:
d^2 = 16t^2 + 18(t-1)^2
d^2 = 16t^2 + 18(t-1)^2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.