Asked by Help Please

Boat A leaves a dock headed due east at 1:00 PM traveling at a speed of 16 mi/hr. At 2:00 PM, Boat B leaves the same dock traveling due north at a speed of 18 mi/hr. Find an equation that represents the distance d in miles between the boats and any time t in hours for t≥1 , using that t=0 corresponds to the time that Boat A leaves the dock.
Answered by Steve
We have a right triangle whose hypotenuse is the distance (d) between the boats:

d^2 = 16t^2 + 18(t-1)^2
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