Asked by Anonymous

A bullet fired vertically upwards reaches a height of 500m. [g=9.8m/s2]. What is its initial velocity?
Answered by Henry
V^2 = Vo^2 + 2g*h.
V = 0, g = -9.8 m/s^2, h = 500 m.
Vo = ?.

Answered by Nataizya
0=v0^2 +2(-9.8m/s^2)(500m)
0=u^2-19.6+1000
0=u+980.4
0-980.4=v0^2
V0^2=-980.4m/s
Answered by Jordon Calder
@Nataizya, why did you add 1000
-->0=u^2-19.6+1000

instead of multiplying?

--->0=u^2-(19.6*1000)
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