Mr. Kasberg rides his bike at 6 mph to the bus station. He then rides the bus to work, averaging 30 mph. If he spends 20 minutes less time on the bus than on the bike, and the distance from his house to work is 26 miles, what is the distance from his house to the bus station?

Answer 1

bike...d = 6t ... d/6 = t

bus... 26 - d = 30 (t - 1/3)

substituting...26 - d = 30 (d/6 - 1/3)

26 - d = 5d - 10

36 = 6d

Answer 2

Kinda helpful