Asked by sma

Which term of the progression 19+ 18 1/5 + 17 2/5 + …is the first negative term? What is the smallest number of terms which must be taken for their sum to be negative ? Calculate this sum exactly.

Answers

Answered by Reiny
Arithmetic series with
a = 19
d = -4/5

a + (n-1)d < 0
19 + (n-1)(-4/5) < 0
19 - (4/5)n + 4/5 < 0
times 5
95 - 4n + 4 < 0
-4n < -99
n > 99/4
n > 24.75
so it must be term(25) which is the first one negative.

check:
term(25) = 19 + 24(-4/5) = -1/5
term(24) = 19 + 23(-4/5) = 3/5
OK

use the formula for sum(n) < 0
to do the 2nd part of your problem
Answered by Hnin
which term of the progression 19+181/5+17 2/5+...is the first negative lterm?which is the smallest number of terrms which must be taken for their sum to be negative?Calculate this sum exactly.
Answered by Anonymous
Please give the second part of question with complete solution
Answered by Anonymous
Solve the second part
Answered by queentosleet
FIND CONSECUTIVE COUNTING NUMBERS WHOSE SUM IS 50.


FIND THE SUM.
19+ 18
how u do this help
Answered by Anonymous
thank you
Answered by prasha
thanks now i know how to solve this
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