Asked by nkule

A box is placed on rough surface.it has a normal force of magnitude 120N.a force of 20N applied to the right cannot move the box.calculate the magnitude and direction of the friction forces
Answered by Rutger<3Physics
If the box cannot move but has a force applied to the right, the force of the friction must be the exact same force but in the opposite direction.
Answered by Rutger<3Physics
A.K.A. Newtons third law of motion.
Answered by masha Mogau
Ff =UsN
Ff=(120)(20)
Ff=2400N