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A 70.0 kg base runner begins his slide into second base while moving at a speed of 4.0 m/s. The coefficient of friction between...Asked by Sandhya
A 66.0 kg base runner begins his slide into second base when he is moving at a speed of 4 m/s. The coefficient of friction between his clothes and Earth is 0.70. He slides so that his speed is zero just as he reaches the base.
(a) How much mechanical energy is lost due to friction acting on the runner?
(b) How far does he slide?
(a) How much mechanical energy is lost due to friction acting on the runner?
(b) How far does he slide?
Answers
Answered by
bobpursley
Wouldn't it be equal the the KEnergy lost? 1/2 mv^2. Then to get the distance, KE=mu*mg*distance.
Answered by
Sandhya
Thanks for your quick help
Answered by
Sammy
bobpursley, what does the mu stand for in your equation?
Answered by
Pandy
Mu is the coefficient of friction (μ).
Answered by
Anonymous
556
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