Asked by Emely
A 1.5 tall student throws a baseball with a horizontal component of velocity of 25m/s. It takes 3.00s to come back to its original height.
d. how far did the ball travel horizontally?
e. What is the initial velocity in the y-direction?
f.At what angle is the baseball thrown?
d. how far did the ball travel horizontally?
e. What is the initial velocity in the y-direction?
f.At what angle is the baseball thrown?
Answers
Answered by
Henry
d. d = Xo*T = 25m/s * 3s. = 75 m.
e. Tr = 3s/2 = 1.50 s. = Rise time.
e. Y = Yo + g*Tr = 0.
Yo - 9.8*1.5 = 0.
Yo = 14.7 m/s = Ver. component of initial velocity.
f. Tan A = Yo/Xo = 14.7/25 = 0.58800.
A = 30.5o.
e. Tr = 3s/2 = 1.50 s. = Rise time.
e. Y = Yo + g*Tr = 0.
Yo - 9.8*1.5 = 0.
Yo = 14.7 m/s = Ver. component of initial velocity.
f. Tan A = Yo/Xo = 14.7/25 = 0.58800.
A = 30.5o.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.