Asked by Lilinau
An 8.7 kg block slides with initials speed of 1.66 m/s across a level floor. How far does the block slide before it comes to rest!?
I used F= m(v(sq)/2s)...is that right?
I used F= m(v(sq)/2s)...is that right?
Answers
Answered by
bobpursley
No. You need the retarding force of friction.
Vf^2=vi^2 + 2ad and you are solving for d. But a=force/mass
and force=mu*mg
Vf^2=vi^2 + 2ad and you are solving for d. But a=force/mass
and force=mu*mg
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