Question
A 4 kg block slides along a frictionless horizontal with a speed of 5.1 m/s. After sliding a distance of 7 m, the block makes a smooth transition to a frictionless ramp inclined at an
angle of 13 degrees to the horizontal.
The acceleration of gravity is 9.81 m/s2.
How far up the ramp does the block slide
before coming momentarily to rest?
Answer in units of m.
angle of 13 degrees to the horizontal.
The acceleration of gravity is 9.81 m/s2.
How far up the ramp does the block slide
before coming momentarily to rest?
Answer in units of m.
Answers
Henry
Wt. of block=m*g = 4kg * 9.8N/kg=39.2 N.
Et = Ek + Ep = 0.5m*V^2
Ek + Ep = 0.5*4*(5.1)^2 = 52 J.
0 + Ep = 52 @ hmax.
Ep = 52 @ hmax
Ep = mg*h = 52
39.2h = 52
h = 1.33 m.
Dist. up ramp = h/sinA = 1.33/sin13=
5.91 m.
Et = Ek + Ep = 0.5m*V^2
Ek + Ep = 0.5*4*(5.1)^2 = 52 J.
0 + Ep = 52 @ hmax.
Ep = 52 @ hmax
Ep = mg*h = 52
39.2h = 52
h = 1.33 m.
Dist. up ramp = h/sinA = 1.33/sin13=
5.91 m.