Asked by shredder
Find the equation of a circle which diameter has the end point A (5, 4), B (7,4 ).
Answers
Answered by
Steve
the midpoint of the diameter is the center of the circle: (6,4)
The radius is half the diameter: 1
(x-6)^2 + (y-4)^2 = 1
The radius is half the diameter: 1
(x-6)^2 + (y-4)^2 = 1
Answered by
shredder
Correct steve
Answered by
shredder
No the answer is
X^2 + y^2 - r^2 - 12x - 8y + 52 = 0
X^2 + y^2 - r^2 - 12x - 8y + 52 = 0
Answered by
shredder
The answer is
X^2 + y^2 - r^2 - 12x - 8y + 52 = 0
X^2 + y^2 - r^2 - 12x - 8y + 52 = 0
Answered by
Reiny
My money is on Steve's correct answer.
Answered by
Afeez
Steve got it but it did nt reach quarter of d workings
Answered by
Melody Oluwasanya
X²+Y² -12x -8y -53 =0
Answered by
Rrrrrr hhhhh
Gfhhhhh giving f fire go tgg food highly fun Friday haha hey ✋ Gigi
There are no AI answers yet. The ability to request AI answers is coming soon!