Asked by Ashley
Jacqueline is 115 miles away from Miranda. They are traveling towards each other. If Miranda travels 9 mph faster than Jacqueline and they meet after 5 hours, how fast was each traveling?
Answers
Answered by
Steve
If Jackie's speed is x, their combined speed is x + x+9 = 2x+9
The cover the 115 miles in 5 hours, so since distance = speed*time,
(2x+9)(5) = 115
The cover the 115 miles in 5 hours, so since distance = speed*time,
(2x+9)(5) = 115
Answered by
Shredder
Distance = 115 miles
Time taken = 5 hrs
Let jacqueline average speed be = a and miranda average speed = a + 9
Jacqueline a.s + miranda a.s = 2a + 9
from,
Average speed * time = distance
5(2a + 9) = 115
10a + 45 = 115
10a = 115 - 45
10a = 70
Divide both sides by 10
A = 7
Therefore jacqueline's speed was 7m/hr and miranda's speed was 7+9 = 16m/hr
Time taken = 5 hrs
Let jacqueline average speed be = a and miranda average speed = a + 9
Jacqueline a.s + miranda a.s = 2a + 9
from,
Average speed * time = distance
5(2a + 9) = 115
10a + 45 = 115
10a = 115 - 45
10a = 70
Divide both sides by 10
A = 7
Therefore jacqueline's speed was 7m/hr and miranda's speed was 7+9 = 16m/hr
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