Asked by Jessica
On calcination 80g of a marble were obtained 42 g of calcium oxide. The degree of purity of marble?
Answers
Answered by
Ms.Black
There are 6 ways you can draw the two marbles to include one red:
RB,RY,RW,BR,YR,WR
There are 4P2 = 12 ways to draw any two marbles
So, P(one red) = 6/12 = 1/2
RB,RY,RW,BR,YR,WR
There are 4P2 = 12 ways to draw any two marbles
So, P(one red) = 6/12 = 1/2
Answered by
bobpursley
CaCO3>>CaO + CO2 is the reaction I assume you are thinking on.
80gmarble*Zpercent*1moleCaCO3/100gCaCO3*ImoleCaO/1moleCaCO3*56gCaO/1moleCaO=42gCaO
solve for Z.
Z=42*100/80*56=93.75 percent.
check my work.
80gmarble*Zpercent*1moleCaCO3/100gCaCO3*ImoleCaO/1moleCaCO3*56gCaO/1moleCaO=42gCaO
solve for Z.
Z=42*100/80*56=93.75 percent.
check my work.
Answered by
Jessica
thank you bobpursley
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