Asked by Cindy
Calculate the total mass of aluminum, with 90% purity, required to produce 448g of iron in the process
Fe2O3 + 2 Al = Al2O3 + 2 Fe
Fe2O3 + 2 Al = Al2O3 + 2 Fe
Answers
Answered by
bobpursley
molesAl*1/.9=molesFe
or
massAl/molemassAl*1/.9=massFe/molemassFe
MassAl=1.11MassFe*molemassAl/molemassFe
MassAl=1.11*448*26.9/55.8 check that.
or
massAl/molemassAl*1/.9=massFe/molemassFe
MassAl=1.11MassFe*molemassAl/molemassFe
MassAl=1.11*448*26.9/55.8 check that.
Answered by
Damon
Iron must be wicked expensive where you live.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.