Ask a New Question

In Figure below the hand moves the end of the Slinky up and down through two complete cycles in one second. The wave moves along the Slinky at a speed of 0.545 m/s. Find the distance between two adjacent crests on the wave.

1 answer

v = f (lambda) so lambda = v/f.
f is two cycles per second (Hz).

Similar Questions

"A slinky that satisfies v = sqrt(T/_mu) is stretched 12m. The mass of the slinky is 0.8kg. The tension on the slinky is 4N.
1. 1 answer
If a student puts their hand on a cold metal doorknob, how will thermal energy move?* 1 point Cold moves from the doorknob to
1. 1 answer
If a student puts their hand on a cold metal doorknob, how will thermal energy move?* 1 point A. Cold moves from the doorknob to
1. 1 answer
If Janie puts her hand on a cold metal doorknob, how will thermal energy move?A. Cold moves from the doorknob to her hand. B.
1. 1 answer

more similar questions