Asked by Drea
In Figure below the hand moves the end of the Slinky up and down through two complete cycles in one second. The wave moves along the Slinky at a speed of 0.545 m/s. Find the distance between two adjacent crests on the wave.
Answers
Answered by
Chanz
v = f (lambda) so lambda = v/f.
f is two cycles per second (Hz).
f is two cycles per second (Hz).
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