Question
How high could a .5kg basketball be launched by a spring, if the spring is compressed by 0.2m and has a constant of 200N/m?
How fast would the basketball be going just as it left the spring?
How fast would the basketball be going just as it left the spring?
Answers
GK
The work done by the spring on the ball is equal to the kinetic energy of the ball as it is launched:
E<sub>k</sub> = (1/2)kx<sup>2</sup>
x is the length of compression, k is the spring constant.
The velocity of the ball can be calculated by using:
(1/2)mv<sup>2</sup> = E<sub>k</sub>
Substitute the values of E<sub>k</sub> and x. Solve for the velocity, v.
E<sub>k</sub> = (1/2)kx<sup>2</sup>
x is the length of compression, k is the spring constant.
The velocity of the ball can be calculated by using:
(1/2)mv<sup>2</sup> = E<sub>k</sub>
Substitute the values of E<sub>k</sub> and x. Solve for the velocity, v.
Hannah
thank you for your help. :)
reni
A rocket moves upward, starting from rest with an acceleration of 25.1 m/s2 for 4.93 s. It runs out of fuel at the end of the 4.93 s but does not stop. How high does it rise above the ground?