Asked by Mohamed

A 543-N physics student stands on a bathroom scale in an 805-kg (including the student) elevator that is supported by a cable. As the elevator starts moving, the scale reads 473 N
A) Find the magnitude of the acceleration of the elevator.
Answered by Damon
F = 543 - 473 = 79 N down on the student

mass of student = 543/g

a = F/m = 79 / (543/9.81)

= 1.43 m/s^2 down

Answered by Mohamed
Not correct but thanks anyway
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