Asked by feather
The point P(2,-1) lies on the curve y=1/(1-x)
If Q is the point (x, 1/(1-x) find slope of secant line.
these are the points
1.5 1.9 1.99 1.999 2.5 2.1 2.01 2.01 2.001
when i calculated it i got a negative number
1/(1-1.5)=-2 but the answer is 2. also would the points be (1.5, 2) 0r (2,2)?
If Q is the point (x, 1/(1-x) find slope of secant line.
these are the points
1.5 1.9 1.99 1.999 2.5 2.1 2.01 2.01 2.001
when i calculated it i got a negative number
1/(1-1.5)=-2 but the answer is 2. also would the points be (1.5, 2) 0r (2,2)?
Answers
Answered by
Damon
first let's look at the derivative (slope at a point)
y = 1/(1-x)
dy/dx = slope = [-1(-1)]/(1-x)^2
bottom always +
so the slope is always positive
now secant from (2,-1) to
( x , 1/(1-x) )
secant slope P to Q =
(1/(1-x) +1) / (x-2)
(1 + 1 - x )/ [(1-x)(x-2)]
= (x-2) / (x^2 - 3x + 2)
if x = 1.5 then
= (-.5 /(2.25 - 4.5 + 2
= -.5 / (-.25)
= + 2 sure enough
y = 1/(1-x)
dy/dx = slope = [-1(-1)]/(1-x)^2
bottom always +
so the slope is always positive
now secant from (2,-1) to
( x , 1/(1-x) )
secant slope P to Q =
(1/(1-x) +1) / (x-2)
(1 + 1 - x )/ [(1-x)(x-2)]
= (x-2) / (x^2 - 3x + 2)
if x = 1.5 then
= (-.5 /(2.25 - 4.5 + 2
= -.5 / (-.25)
= + 2 sure enough
Answered by
feather
it says to round to 6 decimal numbers
so it would for example the first point
(1.5, 2)
then it would be
(1.9,1.111111) right?
so it would for example the first point
(1.5, 2)
then it would be
(1.9,1.111111) right?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.