How many grams of iron can be recovered from 11.8 kg Fe3O4?

I tried to multiply 11.8 kg by the percent composition of iron, but that didn't work.

3 answers

It should.
11.8 kg x (3*55.847/231.539) = ?
Did you use 0.7236 for the factor (72.36%)?
Yes, but I'm doing my chemistry online hw, and it said to round to sig figs. I put 8.54 g, and it said it was wrong. Thank you so much for responding I'm super confused.
Most books now show Fe3O4 as FeO*Fe2O3 (a mixture of Fe(II) and Fe(III) but that shouldn't change any of the calculations. I would have reported 8.54 kg also.