Asked by Anonymous
How many grams of iron can be recovered from 11.8 kg Fe3O4?
I tried to multiply 11.8 kg by the percent composition of iron, but that didn't work.
I tried to multiply 11.8 kg by the percent composition of iron, but that didn't work.
Answers
Answered by
DrBob222
It should.
11.8 kg x (3*55.847/231.539) = ?
Did you use 0.7236 for the factor (72.36%)?
11.8 kg x (3*55.847/231.539) = ?
Did you use 0.7236 for the factor (72.36%)?
Answered by
Anonymous
Yes, but I'm doing my chemistry online hw, and it said to round to sig figs. I put 8.54 g, and it said it was wrong. Thank you so much for responding I'm super confused.
Answered by
DrBob222
Most books now show Fe3O4 as FeO*Fe2O3 (a mixture of Fe(II) and Fe(III) but that shouldn't change any of the calculations. I would have reported 8.54 kg also.
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