Asked by John
How many grams of iron must be oxidized to produce 5.0g of rust? (Fe2O3)
I have no idea how to solve this!
I have no idea how to solve this!
Answers
Answered by
Steve
If your reaction is
4Fe + 3O2 -> 2Fe2O3
then it takes 2 moles of Fe to produce 1 mole of rust.
5.0g of rust is 0.0313 moles
So, how many grams of Fe in 0.626 moles?
4Fe + 3O2 -> 2Fe2O3
then it takes 2 moles of Fe to produce 1 mole of rust.
5.0g of rust is 0.0313 moles
So, how many grams of Fe in 0.626 moles?
Answered by
John
would it be 10? since it takes double the amount of Fe to make rust. 5.0g of rust is .0313 moles, you would multiply it by 2?
Answered by
DrBob222
1. Steve moved the decimal point; that should be 0.0626 mols.
2. John, that answer is not right.
g = mols x molar mass = 0.0626 x 55.85 = ?
2. John, that answer is not right.
g = mols x molar mass = 0.0626 x 55.85 = ?
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