Asked by Anonymous
Rewrite each equation below. Then solve your new equation. Be sure to check your solution using the original equation.
(n+4)+n(n+2)+n=0
(n+4)+n(n+2)+n=0
Answers
Answered by
Steve
(n+4)+n(n+2)+n=0
(n+4)+n(n+2+1)=0
(n+4)+n(n+3) = 0
n+4+n^2+3n = 0
n^2+4n+4 = 0
(n+2)^2 = 0
n = -2
or,
n+2+2 + n(n+2) + n = 0
(n+2)+n(n+2) + n+2 = 0
2(n+2)+n(n+2) = 0
(n+2)(n+2) = 0
(n+2)^2 = 0
(n+4)+n(n+2+1)=0
(n+4)+n(n+3) = 0
n+4+n^2+3n = 0
n^2+4n+4 = 0
(n+2)^2 = 0
n = -2
or,
n+2+2 + n(n+2) + n = 0
(n+2)+n(n+2) + n+2 = 0
2(n+2)+n(n+2) = 0
(n+2)(n+2) = 0
(n+2)^2 = 0
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