Question
I really need help with this question :(
A pentagon has two exterior angles that measure (3x), two exterior angles that measure (2x + 22) and an exterior angle that measure (x + 41). If all of these angles have different vertices, what are the measures of the exterior angles of the pentagon?
A pentagon has two exterior angles that measure (3x), two exterior angles that measure (2x + 22) and an exterior angle that measure (x + 41). If all of these angles have different vertices, what are the measures of the exterior angles of the pentagon?
Answers
Sum of exterior angles of any polygon is 360°.
So if we add up all five exterior angles of the pentagon, we have
2(3x)+2(2x+22)+x+41=360°
Solve for x.
So if we add up all five exterior angles of the pentagon, we have
2(3x)+2(2x+22)+x+41=360°
Solve for x.
The sum of the 5 exterior angles of a pentagon add up to 180°
How can you make use of this fact in solving your problem?
Let me know what you got.
How can you make use of this fact in solving your problem?
Let me know what you got.
never mind my reply,
that should have said 360, not 180
MathMate did it for you.
that should have said 360, not 180
MathMate did it for you.
Thank you very much :D
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