Asked by mya
A pentagon has two exterior angles that measure (3x)°, two exterior angles that measure (2x+22)°, and an exterior angle that measures (x+41)°. If all of these angles have different vertices, what is the measure of the smallest exterior angle?
25°25 degrees
72°72 degrees
75°75 degrees
66°
25°25 degrees
72°72 degrees
75°75 degrees
66°
Answers
Answered by
oobleck
since the exterior angles add up to 360,
2(3x) + 2(2x+22) + x+41 = 360
Now just solve for x and find which of the three values is smallest.
Extra credit: what is the smallest interior angle?
2(3x) + 2(2x+22) + x+41 = 360
Now just solve for x and find which of the three values is smallest.
Extra credit: what is the smallest interior angle?
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