A disk with a rotational inertia of 1.4 kg×m2 and a radius of 0.8 m rotates on a frictionless fixed axis perpendicular to the disk faces and through its center. A force of 5.2 N is applied tangentially to the rim. The angular acceleration of the disk is:

Answer 1

Torque = I alpha

5.2 * .8 = 1.4 alpha

alpha = 2.97 radians/second^2