Asked by Katie
The driver of a car is going 30 m/s slams on his brakes, the car's tires lock, and the car skids to a stop on a level roadway. The kinetic coefficient of friction between its tires and the pavement is 0.75 as it slides. Draw a free body diagram of the car, find its acceleration (deceleration), and find how far the car slides before stopping.
Answers
Answered by
MathMate
Assuming uniform deceleration and constant friction (independent of speed).
Equate energies:
(1/2)mu²=μmgX
X=distance
u=30 m/s
g=9.81 m/s²
Solve for X=61.1621 m
Acceleration
v²-u²=2aX
solve for
a=(0²-30²)/(2*61.1621)
=-7.3575 m/s²
Equate energies:
(1/2)mu²=μmgX
X=distance
u=30 m/s
g=9.81 m/s²
Solve for X=61.1621 m
Acceleration
v²-u²=2aX
solve for
a=(0²-30²)/(2*61.1621)
=-7.3575 m/s²
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