Question
Can you plz give explaination to the solutions steps by steps in brief? Cz i really don't understand how 2 apply the formula when i revise it nw. Thnkz a lot. [g=10 ms^-2] Particles P, of mass 0.3 kg & Q, of mass 0.2 kg are attached to the ends of a light inextensible string. The string passes over a small fixed smooth peg which is at height of 1 m above the horizontal floor. Initally the system is held at rest with the string taut, so that Q is on the floor & P is at a height of 0.5 m above the floor. The system is released. Find the acceleration of P & the tension in the string while the particles are in motion. When P hits the floor it does not rebound. Find the magnitude of the impulse exerted by the floor on P in this impact. At the instant when P hits the floor, the string becomes detached from P. Find the greatest height above the floor reached by Q, &find also the speed of Q when it returns to the floor. When Q hits the floor it does not rebound. Ans> 2 m/s^2, 2.4 N, 0.42 Ns; 0.6 m, 3.46 m/s
Answers
Related Questions
Cn u plz gv explaination 2 d solutions steps by steps briefly?Cz i really dnt understand hw 2 apply...
Cn u plz gv explaination 2 d solutions steps by steps briefly? Cz i really dnt understand hw 2 apply...
Joanna walked 3,000 steps in 24 hours yesterday. How many steps did she walk in 10 hours?(1 point)...
Joanna walked 3,000 steps in 24 hours yesterday. How many steps did she walk in 10 hours?(1 point)...